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Mathematics 29 Online
OpenStudy (abmon98):

Solve inequality |x-1|<|x-2|

OpenStudy (nincompoop):

try

OpenStudy (abmon98):

i squared both sides

OpenStudy (anonymous):

Is 1 less than 1?

OpenStudy (nincompoop):

we want you to try and solve this before we give help

OpenStudy (nincompoop):

lol sith

OpenStudy (anonymous):

This doesn't have a solution.

OpenStudy (abmon98):

(x-1)(x-1)<(x-2)(x-2) x^2-2x+1<x^2-4x+4

OpenStudy (anonymous):

How do you figure you can square both sides?

OpenStudy (nincompoop):

even if you squared both sides, no solution still exists because the condition can never be true

OpenStudy (anonymous):

@Abmon98, So is it \[|x-2|<|x-2|\] or \[|x-1|<|x-2| ?\]

OpenStudy (nincompoop):

because an absolute value |x-1| is the same as sqrt((x-1)^2)

OpenStudy (abmon98):

Second equation @SithsAndGiggles

OpenStudy (nincompoop):

man, type your problem correctly!

OpenStudy (abmon98):

iam sorry

OpenStudy (anonymous):

Ok well \(|x-1|\) equals \(x-1\) or \(-(x-1) = 1-x\)

OpenStudy (anonymous):

Same thing applies for \(|x-2|\).

OpenStudy (anonymous):

So we have four equations... not all of them will work but we can write them anyway: \[ x-1<x-2\\ 1-x<x-2\\ x-1<2-x\\ 1-x<2-x \]Try solving each one.

OpenStudy (abmon98):

i solved the question, thank you for your help @wio :D

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