Question

The system shown has _____ solution(s). y = x + 1 2y - x = 2 I'll give a medal

Answer 1

\(\Large \begin{cases} y=x+1\quad (1) \\ 2y-x=2\quad (2) \end{cases}\)
instead of \(\Large (1)\) into \(\Large (2)\) we get:
\(\Large 2(x+1)-x=2\)
\(\Large 2x+2-x=2\)
\(\Large x=0\Rightarrow y=0+1=1\)