Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <-5, -4>, v = <-4, -3>

Answer 1

\[
\|\mathbf u\|\| \mathbf v\|\cos(\theta) = \mathbf u\cdot \mathbf v
\]

Answer 2

In this case \[
\|\mathbf u\| = \sqrt{\mathbf u \cdot \mathbf u}
\]

Answer 3

sqrt(u * u)? Or.. sqrt[(x-comp)^2 * (y-comp)^2]?

Answer 4

\[\|\mathbf u\|\| \mathbf v\|\cos(\theta) = \mathbf u\cdot \mathbf v\]\[\|\mathbf u\|\ = \sqrt{(-5)^2 +(-4)^2} = \]\[\|\mathbf v\|\ = \sqrt{(-4)^2+(-3)^2}= \]\[\mathbf u\ \cdot \mathbf v = \]\[\cos \theta = \frac{(\|\mathbf u\| \cdot \|\mathbf v\|\ )}{\|\mathbf u\|\ \| \mathbf v\|}=\]