Question

a boy throw a ball with 15 m/sec speed at angle 53 and then find distance travel by ball and max height will ball get and time of flight

Answer 1

@Cubi-Cal @katiebum479 @KissesFromKristine @veeveeniko @Elsa213 @RileyClaim

Answer 2

@kmullis6

Answer 3

@katiebum479 do you have ans of this question

Answer 4

anybody of you have ans please tell me

Answer 5

I dont even know how to do math like at all im sorry

Answer 6

I dont know physics either sorry

Answer 7

@Elsa213 and @Cubi-Cal you both have ans

Answer 8

Math is not my strongest subject, sorry.

Answer 9

any of you know ans

Answer 10

@Somy

Answer 11

@RileyClaim and @Elsa213

Answer 12

please tell me any best way to get out of sadness and boreness

Answer 13

@katiebum479 do you have

Answer 14

@kisstherains

Answer 15

I'm not very good with math. :(

Answer 16

@_Army_Strong_

Answer 17

it is from progetion of object

Answer 18

This is physics btw?? :O

Answer 19

hmm there is no time even given hhh

Answer 20

time is not given you have to find out it

Answer 21

i know

Answer 22

@KissesFromKristine do you have ans

Answer 23

thanks for try i will be your fan for this try

Answer 24

Okay I think I have what you need

Answer 25

if any body want to be my friend you can also be

Answer 26

oh i think we can make simultaneous equations

Answer 27

R = (u^2*sin2x)/g where R is the total distance traveled by the ball thrown, u is the initial velocity and x is the angle to the horizontal the ball was thrown

Answer 28

g is of course the acceleration of free fall (9.81 m s^-2)

Answer 29

i think you can use motion formula
\[v^2 = u^2 + 2as\]
u= o
so
\[v^2 = 2as\]
u have v= 15m/s
and a= 9.81 m/s2
so find S
then now u have S - it'll by hypotenuse in the triangle and we need to find opposite
we have angle so now find X which is going to be maximum height
next use formula \[s= ut + \frac{ 1 }{ 2 }at^2\]
again u is 0 so
\[s= \frac{ 1 }{ 2 }at^2\]
u have S and u know a
so find t