Question

x^2+y^2-8x-6y+9=0

Answer 1

When the non-linear terms are of the form
\[x^2+y^2+...\]
the equation represents an ellipse.
By completing the square, we can put it in the standard form:
\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\]
The equation becomes
\[\frac{(x-4)^2}{(\sqrt{26})^2}+\frac{(y-3)^2}{(\sqrt{26})^2}=1\]