Question

Need help finding region bounded by the curve y=sqrt(x). Medal and fan!

Answer 1

part a is correct

Answer 2

For part b, area of the washer = pi(R^2 - r^2)
\[V = \int\limits_{0}^{4}\pi \{R^2 - r^2\}dy\]
where R = (5 + x^2) and r = 5
Use \(y = \sqrt{x}\) to replace x with y in the integration.

Answer 3

i got 184pi/3

Answer 4

R may be 5 + x instead of 5 + x^2
where x = y^2

Answer 5

YEAH!! got it

Answer 6

6272pi/15

Answer 7

Alright! Sorry about the earlier mistake.

Answer 8

its cool