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Mathematics 7 Online
OpenStudy (anonymous):

A foxhound jumps over the same hurdle. The table shows the height of the foxhound above the ground g(t), in inches, at t seconds: Time (t) g(t) 0 0 0.4 5.44 0.6 6.24 0.7 6.16 0.8 5.76 1.0 4 1.2 0 How can I find the maximum of this table?

OpenStudy (anonymous):

I need to interpret the maximum of the table before I can compare it to the maximum of f(t) = -16t^2 + 26t. But I don't remember how to find the maximum of tables. Can anyone help?

OpenStudy (anonymous):

@aum

OpenStudy (aum):

Go through the numbers in the second column and see which one is the largest and that will be the maximum.

OpenStudy (anonymous):

So 6.24 at 0.6?

OpenStudy (aum):

Yes, the maximum height reached by the foxhound is 6.24 inches and it occurs at t = 0.6 second.

OpenStudy (anonymous):

And (0.8, 10.56) is the maximum of the formula.

OpenStudy (anonymous):

So then, how does it want me to compare them? It only said this--Part A: Compare and interpret the maximum of f(t) and g(t)?

OpenStudy (anonymous):

Er, function.

OpenStudy (aum):

Your (0.81, 10.56) for the maximum of f(t) is correct. Looks like g(t) and f(t) are two different functions. g(t) already start to decrease at 0.7 and 0.8 whereas f(t) keeps increasing at 0.7 and 0.8 until it reaches maximum at 0.81 second.

OpenStudy (anonymous):

It wasn't 0.81, it was 0.8, according to the graph I created...unless that would be wrong.

OpenStudy (anonymous):

Oh, typo?

OpenStudy (aum):

It is actually 0.8125 to be exact. But it is hard to read higher decimal places from a graph.

OpenStudy (anonymous):

Oh.I was using a graphing program, and it said (0.8, 10.56), so that was why I said that.

OpenStudy (aum):

I did not read from a graph. I used calculus or you can find the vertex of a parabola (which is what f(t) is) and it will attain its maximum at t = 0.8125 second. But doesn't matter. They don't specify how many decimal places they want the answer to be.

OpenStudy (anonymous):

So, for the comparing, you think it wanted me to talk about when it declined and/or something else?

OpenStudy (anonymous):

Okay.

OpenStudy (aum):

You can just say (0.6, 6.24) is the maximum for g(t) and (0.8, 10.56) is maximum for f(t). That is basically the comparison.

OpenStudy (anonymous):

Oh. Then I'm done with that question, since I've already done the rest. Thanks!

OpenStudy (anonymous):

I feel like I understand that much better now.

OpenStudy (anonymous):

Can I try?!

OpenStudy (anonymous):

@D3xt3R Sure! With what, exactly?

OpenStudy (aum):

You are welcome. IDK if they are expecting this but this is for your FYI. When we are given the actual function, such as f(t) = -16t^2 + 26t, we can EXACTLY determine the maximum point. When we are given a table we can only arrive at an approximation of the maximum point. The table reaches a maximum of 6.24 at t = 0.6 after which it decreases to 6.16 at t = 0.7. But what happens at t = 0.61? at t = 0.62? Does it continue to increase a little more and then start to decrease. We can't be sure. So t = 0.6 is an approximation.

OpenStudy (anonymous):

I see. That's actually pretty cool, because I didn't know about that.

OpenStudy (aum):

Alright. Time to close this question.

OpenStudy (anonymous):

I agree, although I think that Dexter wants your help.

OpenStudy (anonymous):

...With another question? Because this one is done, Dexter.

OpenStudy (anonymous):

...Yes or no?

OpenStudy (anonymous):

Well, if it's with another question, then I do have a part of one. I'll put in a different question. I don't have that many left.

OpenStudy (anonymous):

Does that sound good, or shouldn't I?

OpenStudy (anonymous):

No worry, I tried to solve your question using a different way.

OpenStudy (anonymous):

Oh. So you wanted to use a different method, and to participate. I see.

OpenStudy (anonymous):

Well, thank you as well, I suppose.

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