Question

2x^2-5x+1=0

Answer 1

you cant factor this so you must use the quadratic formula which is
\[-b \pm \frac{ \sqrt{b^2 - 4ac} }{ 2a }\]
just plug in the points
a = 2
b = -5
c = 1

Answer 2

@FriedRice
Be careful with LaTeX.
The -b term is in the numerator.

Answer 3

You wrote this:

\(-b \pm \dfrac{ \sqrt{b^2 - 4ac} }{ 2a }\)

but you meant this:

\(x = \dfrac{-b \pm \sqrt{b^2 - 4ac} }{ 2a }\)

Answer 4

By making use of factorization formula we find the value of x.
2x^2-5x+1=0
a = 2, b = -5 , c = 1
\[= \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}\]
\[ = \frac{5\pm \sqrt{-5^{2}-4*2*1}}{2*2}\]
\[ = \frac{5\pm \sqrt{25-8}}{4}\]
\[ = \frac{5\pm \sqrt{17}}{4}\]

ICSE board sample papers - http://icse.edurite.com/icse-sample-papers.html