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Integration.
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subsitution method
write \(z^4 = (z^4 -1)+1\)
then factor z^4 -1
y like that @hartnn
because denominator z^2 -1 is one of the factors of z^4-1
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yes @hartnn
so you will simply get (z^2-1)(z^2+1) +1 in the numerator, right ?? now just separate out the numerators :)
what do you mean by separate out..
like (a+b)/c = a/c +b/c
im not sure.. but. (z^2 -1 + 1) (z^2 + 1 +1 )
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|dw:1404542108621:dw| got that ^^ ?
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