Question

how to break 1/(2n+1)(2n+3)(2n+5) into partial fraction

Answer 1

\[\frac{ 1 }{ (2n+1)(2n+3)(2n+5) }\]

Answer 2

Let..
\[\Large \frac{ 1}{(2n+1)(2n+3)(2n+5) } = \frac{A}{2n+1} + \frac{B}{2n+3} + \frac{C}{2n+5}\]

Answer 3

take LCM..solve for A B and C..substitute

Answer 4

ok, got it :)

Answer 5

glad :)

Answer 6

can i solve it by multiplying by (2n+1)

Answer 7

@hartnn

Answer 8

what do u mean ? why only multiply by 2n+1 ?

Answer 9

now substituting by n by -1/2 so getting the value of A

Answer 10

but that won't help you get A,B,C values

Answer 11

repeating the

Answer 12

process again

Answer 13

ok, you can do that

Answer 14

after taking LCM also, you'd put x=-1/2 to find A, its same thing, just different ways of doing.