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The inradius of an equilateral triangle whose one side length is 2, is ..?
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The median, altitude, perpendicular bisector and angle-bisector of an equilateral triangle are all coincident. So the in-radius is one-third of the median AD shown below. Can you figure out the distance OD knowing that OD = (1/3)AD, since the centroid is at 1/3 of the median.|dw:1404736995267:dw|
Ooh, I got the correct answer. Thank you so much!! I wanna ask one thing, is in-radius formula always 1/3 of the height/altitude of the triangle?
Noooo, only for equilateral triangles. For a general triangle, the in-radius is obtained by the intersection of the angle bisectors. Thank you for reminding me to indicate the general method. :)
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