Solve for x: −5|x + 1| = 10
x = 0 x = −3 and x = 1 x = −1 and x = 3 No solution
@tanya123
@hba @jim_thompson5910
First you must isolate the absolute value. So divide both sides by -5 to get \[\Large -5|x+1| = 10\] \[\Large \frac{-5|x+1|}{-5} = \frac{10}{-5}\] \[\Large \frac{\cancel{-5}|x+1|}{\cancel{-5}} = \frac{10}{-5}\] \[\Large |x+1| = -2\] What do you notice about the last equation?
The absolute value is by itself?
what else
I don't know
what does absolute value represent in general?
The value of a number without signs or anything
it also represents distance for example |-7| = 7 and this says "the number -7 is seven units away from 0"
since negative distance makes no sense, it means that the result of an absolute value expression is never negative
Saying \[\Large |x+1| = -2\] makes no sense. So therefore, there are no solutions to that equation.
There is no way to make the left side of \[\Large |x+1| = -2\] equal to -2 (or any negative number for that matter) regardless of any x value you pick.
So if the answer is a negative number, there is no solution?
if you have something of the form |x| = -2 or |x| = -7, then it's not possible so there are no solutions
Thank you!
np
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