Question

help please
will fan and give medals

Answer 1

@am!rah

Answer 2

Hi @deshawn1 I would love to help.

Answer 3

ok thank you

Answer 4

ok

Answer 5

Ok so we can use something called SOH-CAH-TOA to represent

SOH: sinAngle or sin(Theta) = Opposite/Hypotenuse
CAH: cosAngle or cos(Theta) = Adjacent/Hypotenuse
TOA: tanAngle or tan(Theta) = Opposite./Adjacent

And for this problem we are looking for the Tangent or tan(Angle), which is tan(B) which is the angle ABC in this case.

The opposite side to B is 8
The Adjacent side to B is 15

Given this information, I would like you to take a guess at what ratio (quotient) you would use to get the tanB.

Answer 6

SOH-CAH-TOA is something you should memorize as you will never forget how to calculate these in the future!

Answer 7

idk i think the answer is c t

Answer 8

to

Answer 9

Ok so since we are looking for the tanB, we need to use the TOA part. Tangent = Opposite/Adjacent. Since we know Angle B has the parts: Opp = 8 and Adj = 15, then the tanB = 8/15

Answer 10

ok i get it a little now

Answer 11

Opp = Opposite (Side directly across)
Adj = Adjacent (Longest side that is NOT the Hypotenuse)
Hyp = Hypotenuse (Longest Side)