Question

Two moles of compound P were placed in a vessel. The vessel was heated and compound P was partially decomposed to produce Q and R. A dynamic equilibrium between chemicals P,Q and R was established. At equilibrium x moles of R were present and the total number of moles present was (2+x/2). What is the equation for this equilibrium reaction? A) P <-> 2Q+R B) 2P <-> 2Q+R C) 2P <-> Q+R D) 2P <-> Q+2R

Answer 1

You have 2 moles of P so P = 2P.
You it was broken to produce 2 other compounds Q and R.
They are in equilibrium.
The total is represented as (2+x/2) And you have only 2 compounds Q and R.

Answer 2

Also X amount of R was present at equilibrium.

Answer 3

well thanx for sending details...
what is the correct option then???

Answer 4

Try each equation from the option
1)P-->2Q+R
Initial: 2 - -
At equilibrium x moles were present look at the ratio so P at equilibrium will be 2-x and Q will be 2x
Add the total number of moles
2-x+2x+x=2-x+3x=2+2x

2)2P--->2Q+R
initial 2 - -
at equilibrium x moles were present x, look at the ratio so it will be 2-2x and Q will be 2x
add them up. 2-2x+2x+x=2-x

3) 2P-->Q+R
Initial 2 - -
At equilibrium x moles of R were present. Look at the ration so P at equilibrium would be 2-2x and Q will be x.
Add them up
2-2x+2x=2

4)2P-->Q+2R
Initial 2 - -
At equilbrium x moles of R are present, so P will be 2-2x and Q will be x/2.
2R=x
R=x/2 if 1 mole is present add them up
2-x+x+x/2=2
2+x/2