A 26-foot ladder is placed against a house and reaches the 24-foot roof. What is the distance between the base of the ladder and the base of the house if the ground meets the house at a right angle?

2 ft

4 ft

10 ft

8 ft

Question

A 26-foot ladder is placed against a house and reaches the 24-foot roof. What is the distance between the base of the ladder and the base of the house if the ground meets the house at a right angle?



2 ft

4 ft

10 ft

8 ft

anonymous · Answer

wouldnt it be 26^2 + B^2 = 24^2?

johnweldon1993 · Answer

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Not quite...since our hypotenuse will be the 26 that would be the 'c' in our equation

$$\large a^2 + b^2 = c^2$$

we have a and we have c

$$\large 24^2 + b^2 = 26^2$$

johnweldon1993 · Answer

So to solve for the 'b' we would do

$$\large 26^2 - 24^2 = b^2$$

$$\large b = \sqrt{26^2 - 24^2}$$

anonymous · Answer

(X²)=(26²)-(24²), so X= the square root of (676-576), 
so X= 10 ft ( choice C)

anonymous · Answer

answer is 10
?

anonymous · Answer

yes

anonymous · Answer

that is correct

johnweldon1993 · Answer

As said above, correct! :)