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When 6.0 mol H2O react with 5.0 mol Al in the reaction below, 4.0 mol of Al are used up in the reaction. How many moles of Al are left over unreacted? 2 Al + 3 H2O → Al2O3 + 3H2 2.5 mol Al left over 2.0 mol Al left over 1.0 mol Al left over 0.5 mol Al left over
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@FriedRice
how many aluminum were there in the first place? then how many have been used in the reaction? so it would be 5 - 4 =1 Al left over
oh that is easy thanks!
lol yw
:)
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