Hey guys help me out with this and it'll be vastly appreciated. :) Giving medals.
what's the question?
One sec
\[y = \sqrt{4-x} + 3\] explain if its a function find the domain find the range
Can you help?
yes
well domain of a function is all the numbers that can be used in the function.perhaps in this function we can't find f(5) .
got it?
so 4-x must be larger or equal to0: \[4 - x \ge 0\]
got it?
@SeverelyAutistic
Yes
well,did you get it?
\[4 - x \ge 0\]
Yea, is the vertical line test needed at all here?
so \[x \le 4\]
it's the domain ;)
How would I know if its a function?
And yes thank you for the domain part I understood perfectly :D
you know this: |dw:1405439967717:dw|
Don't think I do... could you explain?
you're welcome ;) here if for two x we get the same f(x) it IS NOT a function.
Ahhh So would I need to plug in values and check to see if they have the same results?
no it's not necessary.you can find if it's a function or not easily. for example sqr (4-x) is cannot give us the same f(x) despite the Xs are different!
you get what am i saying?
Yep :D So we got the domain, how about the range?
well,range is all the numbers the function give us! sqr (4-x) can give us at least 0 ... absolutely we cannot get -2 or -4 from sqr (4-x) !
ok?
Hm, so what you're saying is that sqr(4-X), you will always get a positive value, and thus it wouldn't satisfy the domain?
Took me a minute but I think I got it
is that it?
yes ;) sry i want to go...so the sqr (4-x) only give us 0,1,2 and etc...so we'll get at least 0 and we have 3 too, so we'll get at least 3 from the function...so the range is: \[f(x) \ge 3\]
Or, in interval notation, the range is: [3, infinity)
Alright thank you so much, have a medal :)
you're welcome ;)
thanks for medal :)
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