Question

Meteorologist Paul Windward and geologist Rhaina Stone are rushing to a paleontology conference in Pecos Gulch.Paul lifts off in his balloon at noon from Lost Wages, heading east for Pecos Gulch Conference Center. With the wind blowing west to east, he averages a land speed of 30km/h. This will allow him to arrive in 4 hrs, just as the conference begins.Meanwhile, Rhaina is 160 km north of Lost Wages. At the moment of Paul's liftoff, Rhaina hops into an off road vehicle and heads directly for the conference center. At what average speed must she travel to arrive at the same time Paul does?

Answer 1

@jim_thompson5910 i know its long..sorry.. i need help..

Answer 2

First off, what is this distance here?

Answer 3

doesnt say..

Answer 4

hint: it takes him 4 hrs to travel that distance and he's traveling 30 km/hr

Answer 5

do i have to do an equation with it??

Answer 6

distance = rate * time

Answer 7

rate is another term for speed

Answer 8

so..its d=30km/hr*4

Answer 9

forget about the units for a second

Answer 10

they're kinda cluttering things up

Answer 11

ok..

Answer 12

what's the distance from Paul to the Destination?

Answer 13

80..

Answer 14

no

Answer 15

distance = rate * time

don't worry about the units

Answer 16

i really have no clue what to do..

Answer 17

"With the wind blowing west to east, he averages a land speed of 30km/h. This will allow him to arrive in 4 hrs,"

Answer 18

That's given to you

Answer 19

so.. i have to multiply the rate which is the speed times the 4 hrs he is going to take.. to then get the distance??

Answer 20

correct

Answer 21

120..is that correct?

Answer 22

yep