Question

In a Hardy-Weinberg problem, the 2pq represents:

A. homozygous dominants

B. heterozygotes

C. homozygous recessives

D. hemizygous individuals

Answer 1

@N.atia?

Answer 2

im sorry i still didnt take the hardy weinberg principle

Answer 3

@Whitemonsterbunny17 ?

Answer 4

Hello @quickstudent !

Answer 5

In Hardy Weinberg Law i.e \(\large\sf P^2+Q^2+2PQ\),
P\(^2\) = Frequency of homozygous dominant
Q\(^2\) = Frequency of homozygous recessive
2PQ = Frequency of heterozygous.

Answer 6

Got it ?

Answer 7

hardy-weinberg is just a simple algebra of a quadratic equation
\[(a+b)^2 = a^2+2ab+b^2 \] where P is homo dominant and Q is homo recessive, and of course PQ would be homo and homo so that's a hetero
whatever this is, it has no real-world application, though the point of knowing this is just about getting an understanding of distribution of traits under controlled circumstances. NOW, go forth and read your biology/genetics book and learn some more instead of relying on other people :)