How many years will it take for a $50 investment to grow to $1000 if it is compounded continuously at a rate of 5%? Round to two decimal places. Do not include units in your answer A(t) = P ert
\[1000=50e^{.05t}\] solve for \(t\) in 3 steps
1) divide by 50 2) write in equivalent logarithmic form 3) divide by \(.05\)
look familiar ?
Yes lol I just didn't see it in the same set up! Thanks again
yw
btw no one compounds interest continuously that is stuff that happens in nature
Got it. Quick question. What do I dividing by if there nothing infront of the e like this problem.. The price of 9-volt batteries is increasing according to the function below, where t is years after January 1, 1980. During what year will the price reach $5? P(t) = 1.1 e0.047t
not sure what you mean you want \[5=1.1e^{.047t}\]
1) divide by \(1.1\) 2) 3)
Oops I didn't see the 1.1 infront of the e. Ty
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