Question

the solutions to the quadratic equation x^2+5x+4=0 are
A=0 and 1
B=-1and4
C.-1and-1
D.3 and 4
E.there are no real roots

Answer 1

@FriedRice

Answer 2

@PFEH.1999

Answer 3

well you can just simplify the equation

Answer 4

or you can put the equation into the quadratic formula which is
\[-b \pm \frac{ \sqrt b^2 - 4ac }{ 2a }\]

Answer 5

so what would the answer be??

Answer 6

a = 1
b = 5
c = 4

Answer 7

would the answer be B

Answer 8

ok is the answers correct?

Answer 9

i dont see the right answer

Answer 10

thats exacly like the question says

Answer 11

What does answer B say?

Answer 12

-1 and 4

Answer 13

there are real roots but none of A - D makes sense because i got x = -4, -1

Answer 14

ok we can go to next ?

Answer 15

sure

Answer 16

which of the following is equivalent to the equations
11-3x^2+7x-4=8x+1
A.3x^2+15x-6=0
B.3x^2+15x+16=0
C.3x^2+x-6=0
D.-3x^2+x+6=0