Question

solve this polynomial equation. 15x^2-119x^2-10x+16=0

Answer 1

is that 2 x^2 terms in there?

Answer 2

\[15x ^{2}-119x ^{2}-10x+16\]is what you have typed

Answer 3

15x^3 I think

Answer 4

me too

Answer 5

yes and with 15^3

Answer 6

sorry i wrote it wrong

Answer 7

\[15x^3-119x^2-10x+16=0\]

Answer 8

(x-8) is the first root. Now let's find the rest!

Answer 9

once we find the first factor of (x-8) we have the following polynomial left over to factor:\[15x ^{2}+x-2\]I would do this using the quadratic formula cuz it looks hairy.

Answer 10

so you have to factor it out first?

Answer 11

The other factors are this:

Answer 12

\[(x-\frac{ 1 }{ 3 })(x+\frac{ 2 }{ 5 })\]giving you a whole factorization of:\[(x-8)(x-\frac{ 1 }{ 3 })(x+\frac{ 2 }{ 5 })\]

Answer 13

factoring is the only way to solve these.

Answer 14

I used synthetic division to find the first factor by the rules of the Rational Roots Theorem.

Answer 15

ok and then what?

Answer 16

watch. i will do it with 8 so you can see, ok?

Answer 17

That 0 remainder tells us that (x-8) is a root.