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What is the sum of a 7-term geometric series if the first term is 6, the last term is 24,576, and the common ratio is 4?
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-32,766 -19,662 19,662 32,766
@mathmate
Sum of a geometric series is given by: \[\huge S_n= \frac{a(1-r^n)}{1-r}\] \[\huge S_7= \frac{6[(1-4)^7]}{1-4}\] \[\huge S_7= \frac{6[-16383]}{-3}\] \[\huge S_7= 32,766\]
thnx
Note: \(\huge S_7=6\frac{(1-4^7)}{(1-4)}\) The final answer is correct.
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