medals!!!!!
A balloon is released and flies straight up for 6 miles, and then the wind blows it west for 4 miles. Find the distance between the balloon and the site where it was released.
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OpenStudy (imstuck):
You will set this up as right triangle problem and what you are solving for is the hypotenuse of the triangle.
OpenStudy (imstuck):
|dw:1405839776102:dw|
OpenStudy (anonymous):
ok its a sq root answer
OpenStudy (superhelp101):
yah it is a Pythagorean problem
OpenStudy (superhelp101):
use the formula a^2 + b^2 = c^2
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OpenStudy (anonymous):
52
OpenStudy (superhelp101):
so 4^2 + 6^2 =
16 + 36=52
great job!
OpenStudy (anonymous):
but its a sq root answer so 2 sq root 5?
OpenStudy (superhelp101):
what are the other answer choices?
OpenStudy (anonymous):
3 sq root 7
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OpenStudy (anonymous):
2 sq root 3
OpenStudy (anonymous):
and 2 sq root 13
OpenStudy (anonymous):
\[A^2+B^2=C^2\] So if C is the Hypotenuse then:\[C = \sqrt{A^2+B^2}\]
OpenStudy (superhelp101):
then @alyygirl you have to do the square root of 52
OpenStudy (anonymous):
So you really have \[C = \sqrt{52}\]
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OpenStudy (anonymous):
no 2 sq root 13
OpenStudy (anonymous):
You can break up the inside square root into 4 and 13 because 4 times 13 = 52 and you will have:\[\sqrt{4 \times 13}\]
Since 4 is a perfect square of the number 2 and it is multiplied by 13 we can obey the rules of square roots and take the square root of 4 out of the square root sign and multiply it by only square root of 13 like so:\[\sqrt{4 \times 13} = \sqrt{2^2 \times 13} = 2\sqrt{13}\]