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OpenStudy (anonymous):
If log (5x+20)=3, what is the value of x?
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OpenStudy (solomonzelman):
\(\normalsize\color{blue}{ \log(5x+20)=3 }\)
\(\normalsize\color{blue}{ \log(5x+20)=3 \times \log 10 }\)
\(\normalsize\color{blue}{ \log(5x+20)= \log 10^3 }\)
\(\normalsize\color{blue}{ \log(5x+20)= \log 1000 }\)
OpenStudy (solomonzelman):
can you finish it ?
OpenStudy (anonymous):
no im kinda confused I thought when you had addition it turns into a product
OpenStudy (solomonzelman):
I am just giving you the fastest approach...
OpenStudy (anonymous):
so what do I do after?
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OpenStudy (solomonzelman):
If \(\normalsize\color{blue}{ \log a= \log b }\) then \(\normalsize\color{blue}{ a= b }\)
OpenStudy (anonymous):
doesn't make any sense
a)-19/5
b)-17/5
c)196
d)204
OpenStudy (anonymous):
@SolomonZelman
OpenStudy (solomonzelman):
this what doesn't make sense, how can you ask questions about factoring (algebra 1) and about logarithms (trigonometry) at the same time ?
OpenStudy (anonymous):
ib mathematics
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OpenStudy (anonymous):
x=196 (:
OpenStudy (anonymous):
thankyou
OpenStudy (anonymous):
\[\log (5x+20)=3,\] means
\[5x+20=10^3\]
OpenStudy (anonymous):
they say the same thing exactly
that you can solve for \(x\) without much trouble
OpenStudy (solomonzelman):
I forgot to use just that relation -:(
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OpenStudy (anonymous):
\[5x+20=1000\\
5x=980\\
x=196\]
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