Question

the parabolas y=-3x^2+10x-6 and y=-3x^2-17x+2 intersect at
A.they do not intersect
B.x=sq rt2/3 and x=-sq rt2/3
C.x=8/27
D.x=8/27 and x=-4/27

Answer 1

your job is to set
\[-3x^2+10x-6=-3x^2-17x+2\]and solve for \(x\)

Answer 2

shouldn't be too hard since it is the same as
\[10x-6=-17x+2\]

Answer 3

a) add \(17x\) to both sides
b) add \(6\) to both sides
c) divide both sides by \(27\)

Answer 4

whats the answer i got c

Answer 5

@mathmate can u help ,e

Answer 6

What did you get for x?

Answer 7

17

Answer 8

How did you get 17?
Did you solve for x as @satellite73 showed you?

Answer 9

yea i got C is that correct

Answer 10

What did you get for x again?

Answer 11

17

Answer 12

C doesn't say x=17! :)

Answer 13

none of them do so would it be A

Answer 14

@Twilliams250
There are two ways to do math:
1. Get the answers, and get 90 for assignments, but fail at exams.
2. Put work in there, learn how to solve problems, get perhaps 70 for assignments, but get the same for exams.
Your choice is:?

Answer 15

2

Answer 16

Very good! So you want to follow what @satellite73 gave you as instructions to solve for the value of x. Then come back here and check you answers. If the answer is not correct, we'll help you get there.

Answer 17

need help

Answer 18

Start with @satellite73's post:
shouldn't be too hard since it is the same as
10x−6=−17x+2

a) add 17x to both sides
b) add 6 to both sides
c) divide both sides by 27

Can you do them step by step?

Answer 19

still having trouble

Answer 20

Can you reproduce the starting statement, meaning the equation
"10x-6=-17x+2"

Answer 21

yea

Answer 22

@mathmate

Answer 23

Now below it, work out step (a) and tell me what you've got.