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OpenStudy (anonymous):
You are given the following function.
f(t) = t + √t
Find the derivative of the function using the definition of derivative.
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terenzreignz (terenzreignz):
Yikes...
\[\Large f(t) = t + \sqrt t\]
\[\Large f'(t) = \lim_{h\rightarrow 0}\frac{f(t+h)-f(t)}{h}\]
This will not be pretty lol
terenzreignz (terenzreignz):
I'm sure you've gotten at least that^ far.
What you have got now? ^_^
OpenStudy (anonymous):
\[1 + \lim_{h \rightarrow 0} \frac{ \sqrt{t + h} - \sqrt{t}}{ h } \]
what's next?
terenzreignz (terenzreignz):
Hmmnn...
terenzreignz (terenzreignz):
argh... this is why nobody does it this way XD...
hang on
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terenzreignz (terenzreignz):
Okay, try multiplying with this:
\[\Large \frac{\sqrt{t+h}+\sqrt t}{\sqrt {t+h}+ \sqrt t}\]
terenzreignz (terenzreignz):
@swedishlad bet you already got there before me xD
OpenStudy (anonymous):
\[1 +\lim_{h \rightarrow 0}\frac{ h }{ h(\sqrt{t+h}+\sqrt{t}) }\]
terenzreignz (terenzreignz):
You can cancel out the h now
\[\Large 1 +\lim_{h \rightarrow 0}\frac{ \cancel h }{ \cancel h(\sqrt{t+h}+\sqrt{t}) }\]
terenzreignz (terenzreignz):
And you'd be done lol
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OpenStudy (anonymous):
\[\frac{ 1 }{ 2\sqrt{t}} + 1\]
OpenStudy (anonymous):
boom, thanks man
terenzreignz (terenzreignz):
No problem ^_^
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