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Physics 18 Online
OpenStudy (akohl):

@Abhisar . A car of mass 1091 kg climbs a 5.0° slope at a constant speed of 80km/h Assuming that air resistance and friction with the road may be neglected, at what rate must the engine deliver mechanical energy to the car? 238 kW 31 kW 21 kW 39 kW

OpenStudy (abhisar):

|dw:1405956783956:dw|

OpenStudy (akohl):

With you so far... what's next

OpenStudy (abhisar):

Can u tell me the value of theta here ?

OpenStudy (akohl):

5

OpenStudy (abhisar):

\(\huge\checkmark\)

OpenStudy (akohl):

So what's the equation

OpenStudy (abhisar):

Rate of work done = power. And power = F.v = \(\sf \frac{W}{T}\)

OpenStudy (abhisar):

Force acting on the car will be mg.sin5° = ?

OpenStudy (akohl):

931.85

OpenStudy (abhisar):

Now calculate power by multiplying it with velocity.

OpenStudy (akohl):

I'm getting 74548

OpenStudy (akohl):

Now what

OpenStudy (abhisar):

u converted 80 km/hr into m/s first ?

OpenStudy (akohl):

Oh

OpenStudy (akohl):

Thanks got 21 as my final answer

OpenStudy (abhisar):

\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)

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