@Abhisar
. A car of mass 1091 kg climbs a 5.0° slope at a constant speed of 80km/h Assuming that air resistance and friction with the road may be neglected, at what rate must the engine deliver mechanical energy to the car?
238 kW
31 kW
21 kW
39 kW
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OpenStudy (abhisar):
|dw:1405956783956:dw|
OpenStudy (akohl):
With you so far... what's next
OpenStudy (abhisar):
Can u tell me the value of theta here ?
OpenStudy (akohl):
5
OpenStudy (abhisar):
\(\huge\checkmark\)
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OpenStudy (akohl):
So what's the equation
OpenStudy (abhisar):
Rate of work done = power. And power = F.v = \(\sf \frac{W}{T}\)
OpenStudy (abhisar):
Force acting on the car will be mg.sin5° = ?
OpenStudy (akohl):
931.85
OpenStudy (abhisar):
Now calculate power by multiplying it with velocity.
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OpenStudy (akohl):
I'm getting 74548
OpenStudy (akohl):
Now what
OpenStudy (abhisar):
u converted 80 km/hr into m/s first ?
OpenStudy (akohl):
Oh
OpenStudy (akohl):
Thanks got 21 as my final answer
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OpenStudy (abhisar):
\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\)
\(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)