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Find the midpoint of side EF. Figure EFGH is shown. E is at negative 2, 3. F is at 1, 6. G is at 4, 3. H is at 1, 0. (-1, 4) (-0.75, 4.25) (-0.5, 4.5) (-0.25, 4.75)
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Use the midpoint formula:\(\large (\frac{(x2+x1)}{2},\frac{(y2+y1)}{2})\) Since we need to find the midpoint of EF, we will use the coordinates (-2,3)(1,6) so x2=1, x1=-2, y2=6 and y1=3 Can you plug those into the formula?
i got 3/2 and 9/2
Almost, except the x coordinate is negative because -2+1=-1 It is at \((-\frac{1}{2},4\frac{1}{2})\)
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