I can't solve this trig equation, can somebody help. sec(x)-tan(x)=sqr3/3
\[\sec(x)-\tan(x)=\frac{ \sqrt{3} }{ 3 }\]
@IMStuck
give me one sec ok? I will work on it while I help this other person get through his dilemmma then I will be here, ok?
Yeah no problem
i'm here...working on it now...
what exactly are you doing with this? Proving that the left side equals the right side?
no the book says to solve the trigonometry equation.
using trig identities
I am not finding any way in which to get this to a quadratic type of equation to solve. I get this when I use the identities:\[\frac{ 1-\sin(x) }{ \cos(x) }=\frac{ \sqrt{3} }{ 3 }\]And you need to get the sin and the cos to be either one trig function or the other. There is no identity to use that combines a single sin and a single cos into one trig function. Not so far as I know, at least. Are you sure you didn't omit a ^2 in there or something?
No, i have tried too and i don't know to what trig identity to relate it to.
In one of the examples of the book it says to make it equal to zero.
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