the probability that a dessert contains chocolate is 74%. the probability that a dessert contains both chocolate and nuts is 24%. find the probability that a randomly chosen chocolate dessert contains nuts.

Question

driftracer305 · Answer

@ganeshie8

driftracer305 · Answer

i am guessing 0.74*0.24 = 0.1776  = 17.8%......... is that right?

ganeshie8 · Answer

P(nuts | chocolate) = P(chocolate AND nuts) / P(chocolate)

driftracer305 · Answer

so 0.24*0.74 / 0.74......?

ganeshie8 · Answer

nope,
you're given :

 P(chocolate AND nuts)  =  24% = 0.24
 P(chocolate) = 74% = 0.74

just divide

ganeshie8 · Answer

P(nuts | chocolate) = P(chocolate AND nuts) / P(chocolate)
                              = 0.24/0.74
                              = ?

driftracer305 · Answer

ahh ok i see......... but when i made a tree diagram.... i thought that for nuts you would put it as 24%..........

driftracer305 · Answer

so what if it asked for just chocolate without nuts? @ganeshie8

ganeshie8 · Answer

then we need more info i guess..

driftracer305 · Answer

ohh ok..... thank you sir...... @ganeshie8  thx a lot......

ganeshie8 · Answer

yw!

ganeshie8 · Answer

I think we can calculate  just chocolate without nuts ! 
contingency table makes it clear to see :

|dw:1406019044997:dw|