Question

Need help!

Answer 1

ok on what?

Answer 2

@BreeBree13

Answer 3

\[\sqrt{x+16}-\sqrt{x-2}=0\] Solve for X

Answer 4

move sqr x-2 to the other side...it would be:

\[\sqrt{x+16} = \sqrt{x-2}\]

Answer 5

I have the choice between
A:3
B:7
C:9
D:15

Answer 6

then u can say:

\( (\sqrt{x+16})^2 = (\sqrt{x-2})^2 \)

Answer 7

and now it would be x+16 = x-2 and now solve for x ;)

Answer 8

are u sure the problem is right ?@BreeBree13

Answer 9

can u do the rest ?

Answer 10

yes @Hamoody1996 it's incorrect ;)
but i wanted her to reach this herself ;)

Answer 11

It's inconsistent, no solution

Answer 12

ohh okay that make sense now. yes i get it now @PFEH.1999 and yeah @Hamoody1996

Answer 13

It is. I got -7

Answer 14

how?

Answer 15

please write ur solution step by step.

Answer 16

I think you typed the problem incorrectly if you got that

Answer 17

hold on...

Answer 18

opps yeah i did miss type the problem its \[\sqrt{X+16}-\sqrt{X}-2=0\]

Answer 19

ok do the thing i said u above.

Answer 20

I was looking at the wrong problem with the -7, sorry im watching 3 kids as i do this

Answer 21

well keep sqr(x+16) - sqr(x) at one side and at the other side keep 2 so it would be:

\[x+16+x - 2\sqrt{x^2 + 16} = 4\]

Answer 22

and the do this:

\[2x + 12 = 2\sqrt{x^2 + 16}\]

Answer 23

can u do the rest ?

Answer 24

would you put the one side in ( )

Answer 25

Like this?\[2x+12=2(\sqrt{x^2+16})^2\]

Answer 26

no you should write \((2\sqrt{x^2+16})^2 \)

Answer 27

oh okay

Answer 28

does x^2 cancel out?

Answer 29

yes

Answer 30

you'll only find one answer to this equation.

Answer 31

so it should it look like this?\[2x+12=(2+x+16)^2\]

Answer 32

@PFEH.1999

Answer 33

sry@BreeBree13 sry alot something happened and i had to leave ... well not really it should be :

\( (2\sqrt{x^2+16})^2 = 2x^2 + 32\) and the other side should be : \((2x+12)^2\)