Question

Need help with another question. It will be posted below.

Answer 1

\[\sqrt{X+16}- \sqrt{X}-2=0\] solve for x @SolomonZelman can you help me out?

Answer 2

\(\normalsize\color{blue}{ \sqrt{x+16}-\sqrt{x}-2=0 }\)
\(\normalsize\color{blue}{ \sqrt{x+16}-\sqrt{x}-2\color{red}{+2} =0\color{red}{+2} }\)
\(\normalsize\color{blue}{ \sqrt{x+16}-\sqrt{x}=2 }\) square both sides,
\[R ule:~~~~~~ (a-b)^2=a^2-2ab+b^2\]
\(\normalsize\color{blue}{ (x+16)-2\sqrt{(x+16)(x)} +(x)=2 }\)
\(\normalsize\color{blue}{ x+16-2\sqrt{x^2+16x} +x=2 }\)
\(\normalsize\color{blue}{ 2x+16-2\sqrt{x^2+16x} =2 }\)
\(\normalsize\color{blue}{ 2(x+8-1\sqrt{x^2+16x}) =2 }\)
\(\normalsize\color{blue}{ x+8-1\sqrt{x^2+16x} =1 }\)

Answer 3

\(\normalsize\color{blue}{ x+8-1\sqrt{x^2+16x} =1 }\)
\(\normalsize\color{blue}{ x+8-\sqrt{x^2+16x} =1 }\)
\(\normalsize\color{blue}{ x+8-\sqrt{x^2+16x}\color{red}{-x-8 } =1\color{red}{-x-8 } }\)
\(\normalsize\color{blue}{-\sqrt{x^2+16x} =-x-7 }\)

Answer 4

multiply every thing times -1, and you get \(\normalsize\color{blue}{\sqrt{x^2+16x} =x+7 }\)

Answer 5

square both sides, and finish this problem. Lets me know if you need more help.

Answer 6

i don't think that's how you do it. I'm doing radical equation