Which of the following is a solution of x2 - 8x = -27?
negative 4 minus i square root of 11 4 plus i square root of 11 negative 4 minus i square root of 44 4 plus i square root of 44
\[\large{-4 - i\sqrt{11}}\] \[\large{4+i\sqrt{11}}\] \[\large{-4-i\sqrt{44}}\] \[\large{4+i\sqrt{44}}\]
These are the options ?
correct
Okay what do you think the answer should be and why ?
Have you tried it ?
I have but I think im trying it wrong
The equation given in the question is: \[\large{x^2 - 8x = -27}\] \[\large{\implies x^2 - 8x + 27 = 0}\] Okay what did you try ?
You can compare this equation with the general quadratic equation: \[\large{ax^2 + bx + c = 0}\] On comparing, you can find out a,b and c. Using these values and using quadratic formula we can find out the solution of the equation: \[\large{x = \cfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}\]
ohh I wrote the number different hold on let me try that
Sure :)
so I tried but im still clueless
Its okay. What have you tried ?
what I tried was wrong, how should I solve this?
Well follow this method: \(\color{blue}{\text{Originally Posted by}}\) @vishweshshrimali5 You can compare this equation with the general quadratic equation: \[\large{ax^2 + bx + c = 0}\] On comparing, you can find out a,b and c. Using these values and using quadratic formula we can find out the solution of the equation: \[\large{x = \cfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}\] \(\color{blue}{\text{End of Quote}}\) Step by step First find out a,b and c
how do I find that? can u write the equation and I solve it?
Okay lets see: \[\large{x^2 - 8x + 27 = 0}\] \[\large{ax^2 + bx + c = 0}\]
Now lets compare both equations
alright
In first equation coefficient of x^2 = 1 In second it is = a So, a = 1
Now similarly find out b
b is 8? c is 27?
c is correct Check the sign of b again
In first equation coefficient of x = -8
Don't forget the minus sign
okay so b is -8
@vishweshshrimali5
You now have the a , b , and c to use in your quadratic formula.
@ChristopherToni
can you help me? @ChristopherToni
Up to this point, you've determined that a=1, b=-8 and c=27. Plugging this into the quadratic formula gives us \(\large x=\dfrac{-(-8) \pm \sqrt{(-8)^2-4(1)(27)}}{2(1)}\). What do you get when you simplify this? :-)
I troed and I got |dw:1406083004595:dw|
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