Question

Two terms:
y = –2x^2 + 6
y = -0.1x^2 + 6

Answer 1

You are basically making a coaster
Create an equation that will be steeper than both equations, and explain your reasoning.Is what I needed help with

Answer 2

I know they are both conics
y = (-1/10) x2 + 6 has the lines of the conic touch -8 and 8 on the x-axis, with the conic from question A has it touching -2 and 2 on the x - axis

Answer 3

@aum @phi @mathmale @mathstudent55

Answer 4

@ikram002p

Answer 5

@Destinymasha

Answer 6

@SolomonZelman

Answer 7

@ganeshie8 @phi

Answer 8

@undeadknight26

Answer 9

@PFEH.1999

Answer 10

Thank you for coming

Answer 11

"steeper" means a small step in x causes a large step in y

y = –2x^2 + 6

here, if we move from x=0 (y=6) to x=1 (y=4)
y goes down by 2

if we put a bigger number in front of the x, it gets steeper
y = -4x^2 + 6

at x=0 y = 6
at x=1 y = 2
we go down by 4, which is a steeper drop

Answer 12

This is the answer?

Answer 13

Create an equation that will be steeper than both equations,

that means make the coefficient of the x^2 term bigger (in absolute terms)

Answer 14

Alright then
So like you said
y = -4x^2 + 6 for the first one
y = -(1/20)x^2 + 6

Answer 15

I think they just want ONE equation that is steeper than BOTH.

Answer 16

So y = -4x^2 + 6

Answer 17

That will do. But you have to explain your reasoning.

In y = ax^2 +b, increasing the magnitude of a, that is the absolute value of a, has the effect of stretching the graph vertically, making it steeper.

Answer 18

Thanks @aum

Answer 19

You are welcome.