Question

@camerondoherty

Answer 1

@driftracer305

Answer 2

please help will medal

Answer 3

Is this a test?

Answer 4

no @Bobmath

Answer 5

@Destinymasha

Answer 6

@Vane11

Answer 7

@aaronq

Answer 8

@ganeshie8

Answer 9

@hba

Answer 10

@harrychess

Answer 11

@BlackLabel

Answer 12

Please don't tag me Again

Answer 13

okay but can you solve the problem please

Answer 14

geez sorry

Answer 15

1. \[7\sqrt{3}-4\sqrt{6}+\sqrt{48}-\sqrt{54}\]

\[\sqrt{54} = \sqrt{2*3^3}=3\sqrt{2}\sqrt{3}\]

\[7\sqrt{3}-4\sqrt{6}+\sqrt{48}-3\sqrt{2}\sqrt{3}\]

\[7\sqrt{3}-4\sqrt{6}+sqrt{2^4*3}\]

because

\[\sqrt{48}=\sqrt{2^4*3}=2^2\sqrt{3}\]

\[11\sqrt{3}-7\sqrt{6}\]

Answer 16

Use the same sort of method for the rest, good luck.

Answer 17

wait but whats the answers for both of them

Answer 18

Just simplify the square root 10 and 8 as I did on the other question.

\[\sqrt{8}=\sqrt{2^3}=2\sqrt{2} \implies \sqrt{10}*2\sqrt{2}\]

Answer 19

Finish it off.

Answer 20

@jagr2713

Answer 21

I might have been rude but at least I didn't ask for nudes, I helped him through private message and that's my thanks @Fire_Fighter_Of_Miami

Answer 22

i was just kidding lol

Answer 23

why are you typing so long