Question

arithmetic sequence question!

find t50 from: 3,9,15,21

Answer 1

I got disconnected sorry

Answer 2

So you are to find the 50th term of this sequence. You can see that you go ` + 6 ` each time to find the next term. You know that your 1st term is 3.

For instance, if you were to find the 2nd term, you would add 6 once (and you would get 9)
And if you were to find the 3rd term, you would add 6 twice (and you would get 12)

So to find the 50th term, you would add number 6 49 times.

3 + 6 + 6 + 6 + \(\Large\color{black}{ ~^{49~~\rm{ times} } }\) ••••••

instead of adding all 49, would it be easier to say,
3 + (6 × 49) ?

Answer 3

Can you finish the calculations (for the 50th term) ?

Answer 4

so t50 = 441?

Answer 5

t50 = 3 + (6 × 49) (this is not 441)

Answer 6

oh so i get it; you just plug in tn - a + d (n-1) ?

Answer 7

oh whoops

Answer 8

\(\large\color{midnightblue}{ t_n = t_1 + d(n-1) }\)

Answer 9

\(\large\color{midnightblue}{ t_{50}=3 +6(50-1) }\)

Answer 10

need more help, or good from here ?

Answer 11

so then it's
t50 = 9(49)? im confused...

Answer 12

No,

\(\large\color{midnightblue}{ t_{50}=3 +6(50-1) }\)

\(\large\color{midnightblue}{ t_{50}=3 +6(49) }\)

fisrt multiply 6×49 and only then add 3.

Answer 13

oh okay so that's 297...thank you for your help! i appreciate it :D

Answer 14

Anytime :)

Answer 15

(I learned the sequences in trigonometry, not in Alg1..... )