If the domain of each of the functions f(x) and g(x) is all real numbers, will the domain of (f/g)(x) also be all real numbers? Why or why not?
hi, can you help me?
What are YOUR thoughts on this? Suppose that g(x) were x-2. Does this make it any easier for you to answer this question?
No, I am really confused on how (f/g)(x) could even be a function
noo he left :c
nvm
I did not leave. OpenStudy's connection is interrupted every now and then and nothing goes through. I was typing a response to you when this happened.
Given two functions f and g, you can find their sum, difference, product, quotient, composition, and so on.
ok...
(f/g)(x) is the QUOTIENT of functions f and g: f divided by g.
ok...
Take a look at (f/g)(x) when g(x)=x-2: It is f(x) ------ x-2 What is the domain of this new function?
What does "domain" mean to you?
x-2
domain means the x values
it means more than that, actually. Domains are written either as (1) the set of all PERMITTED x values or (2) the values at which the function is NOT defined. x-2 is not a domain; it is an algebraic expression. What x value can f(x) ---- x-2 not be evaluated at? and why?
x has to be greater than 3 right? @mathmale
Actually, x can NOT be = to 2. x can take on any other value. so "x has to be greater than 3" is too restrictive. What is the domain of f(x) -------- x-2 When the domain of f(x) is "the set of all real numbers?"
Oh ok I get it now! @mathmale
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