Help please?? Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share?

Question

anonymous · Answer

|dw:1406416688001:dw|

anonymous · Answer

@mathstudent55

anonymous · Answer

@ganeshie8 can you help me with this problem please?

crashonce · Answer

sin x = opp/hyp = 5/13 (13 is the third side from pythagoras
cos y = adj/hyp = 5/13
Thus sinx = cos y

anonymous · Answer

Wait, how did the 13 come in? Sorry I don't follow.

crashonce · Answer

using pythagoras, the hypotenuse is equal to the squareroot of the sum of the other sides squared so:
$$hypotenuse = \sqrt{12^2+5^2}$$

anonymous · Answer

$$\sqrt{144+25}=\sqrt{169}=13$$
Ok I get that! thanks @CrashOnce

anonymous · Answer

So is that the final answer?

crashonce · Answer

yes 13 is the hypotenuse thus:
sin x = opp/hyp = 5/13 (13 is the third side from pythagoras
cos y = adj/hyp = 5/13
Thus sinx = cos y
no problem

anonymous · Answer

What is the relationship do the ratios of sin x° and cos y° share?

anonymous · Answer

Is it just that they are equal?

crashonce · Answer

yea they are equal

anonymous · Answer

K, tysm