Question

Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A.
Launch area=(1, 2)
Point A=(0, 3)

Answer 1

It is on a graph from 0 in the middle and up to 5 on each of the four ends

Answer 2

first get the slope from both points
okay
do u know how to take out the slope from them

Answer 3

m=y2-y1/x2-x1

Answer 4

yes apply it here

Answer 5

m=3-2/0-1

Answer 6

m=1/-1

Answer 7

yes m=-1 okay now use point slope form

Answer 8

Ok, hold on

Answer 9

Is it y+2=-1(x-1)

Answer 10

y=-1x+0

Answer 11

your math is incorrect double check it

Answer 12

@LydiannAquino

Answer 13

Ok

Answer 14

I'll be back hold on please.

Answer 15

okay

Answer 16

y-(-2)=-1(x-1)

Answer 17

ok take off the parentheses

Answer 18

y+2=-1x+2

Answer 19

y+2=-x+1 not -x+2

Answer 20

that was the mistake you made

Answer 21

Oh, I see it

Answer 22

ok now we need standard form

Answer 23

y-y1=m(x-x1)
y-2 =-1(x-1)
y-2=-1x +1
y=-1x+1+2
y=-x +3 now in the standard from
x+y-3=0
x must be +ve for standard form

Answer 24

oh he is right it should be y-2=-x+1 not what you wrote

Answer 25

so y=-x+3

Answer 26

Ok.

Answer 27

x+y-3=0 , he already gave you standard form

Answer 28

ax+by+c=0

Answer 29

The answer is y=-x+3 right

Answer 30

and in slope intercept form it is y-2 =-1(x-1)

Answer 31

That is correct! however they asked for standard form
y=-x+3 is slope intercept form
and y-2=-(x-1) is point slope from not slope intercept form

Answer 32

the final correct answer is X+Y-3=0

Answer 33

Is'nt standard form y=mx+b

Answer 34

No that's slope intercept form

Answer 35

y=-x+3 is standard form nad slope intercept form is y-y1=m(x-x1)

Answer 36

a line is Ax+By+c in standard form

Answer 37

check here
http://www.mathsisfun.com/algebra/linear-equations.html

Answer 38

Ok so X+Y-3=0 that's standard form

Answer 39

Yep!

Answer 40

Now, are you able to place it so I can see how we worked it all out?

Answer 41

Ax+By=c or Ax+By+c=0 you could see this as the standard form

Answer 42

Yes, that's what I saw through the link you sent me.

Answer 43

alright let me write the summary of what we worked here

Answer 44

Ok.

Answer 45

First we found the slope using the two given points (1,2) and (0,3)
m=3-2/0-1=-1
Second we use the formula (y-y1)=m(x-x1) which is point slope form
it doesn't matter what point you choose the answer will the same
y-2=-1(x-1) ===> y-2=-x+1 ==> y=-x+3
we found the slope intercept form
third step is the put x and y in one side to get the standard form that we want
x+y=3

Answer 46

this is what we did!

Answer 47

I prefer to leave this way x+y=3 since textbooks do so

Answer 48

so y=mx+b is not standard form I asked my teacher and she said it was correct but then... I'm really confused...??

Answer 49

No, it is not! that's slope intercept form. check your textbook

Answer 50

Oh, no you're correct I just looked it up myself...sorry

Answer 51

No problem!

Answer 52

y=-x+3 is slope intercept form, right? How did we get that answer for the next question?

Answer 53

Yes! we got it from this (y-y1)=m(x-x1)

Answer 54

y-2=-(x-1) <this?

Answer 55

Yes!

Answer 56

we just took out the parentheses and subtracted 2 from both sides

Answer 57

I mean added 2 to both sides

Answer 58

Ok I got it. Thank you very much, for everything

Answer 59

Pleasure to help you! Cheers

Answer 60

Would any restrictions apply to the domain and range of this equation? Explain your reasoning using complete sentences.
This is my last question could you help me?

Answer 61

@xapproachesinfinity

Answer 62

I will be back,

Answer 63

Ok.

Answer 64

So, is the question related to this function f(x)=-x+3 or something else?