Why is it better to write a net ionic equation for this reaction (justify): Ca(OH)2(aq) + Na2SO4 --> ?
@JoannaBlackwelder
That depends on what you are writing the reaction for. Is there any more context to this problem?
"conditions around a hydrothermal vents deep in the ocean floor can enable chemical reactions that produce solid materials. A student models one of these reactions by combining aqueous Ca(OH)2 and Na2SO4, and observes the formation of a solid in a liquid. Justify the choice of a net ionic equation for describing this reaction and write the balanced net ionic equation."
@JoannaBlackwelder
A reaction of aqueous solutions to produce a solid and a liquid sounds like a precipitation reaction to me.
The net ionic reaction shows how the precipitate is formed and everything else just stays as ions in solution.
Net reactions are always useful for precipitation reactions. Make sense?
yeah... how do I make a net ionic equation for this? @JoannaBlackwelder
First, do double replacement.
Then check your products to determine which one is the precipitate and which one stays in solution using a solubility table.
Ca(OH)2(aq) + Na2SO4 --> CaSO4 + 2NaOH
Yup
the precipitate is CaSO4
Good. :)
what now?
Now we need to write the reactants and products as they would be in solution, as ions (for everything except the precipitate).
So, Ca(OH)2 would be Ca2+ + 2OH-, for example.
huh?
Ca(OH)2 written as ions is \[Ca ^{2+}+2OH ^{-}\]
This is how the compound exists in solution (aqueous)
oh ok yeah
Can you write out the other aqueous compounds as ions?
Na2SO4 --> Na1+ + 4SO 2NaOH --> 2Na+ + 2OH- ?
NaOH looks good! :)
Look at Na2SO4 again.
hmmm... not really sure how to do this
\[Na _{2}SO _{4}\rightarrow2Na ^{+}+SO _{4}^{2-}\]
Make sense?
why is na only + and so is 2-?
Na has 1 valence electron, and it loses that electron to make an ion, making it +1
oh ok
SO4 is a polyatomic ion that has a charge of 2-
got it got it
:)
So, can you write the whole reaction with the aqueous compounds as ions?
Ca(OH)2(aq) + Na2SO4 --> 2Na+ + SO2− + 2Na+ + 2OH-
\[Ca ^{2+}+2OH ^{-}+2Na ^{+}+SO _{4}^{2-}rightarrowCaSO _{4}+ 2Na ^{+}+2OH ^{-}\]
Make sense?
OHHHHHHH that makes a lot more sense
:)
Now cancel out anything that is on both sides.
is that my net ionic equation though?
No, that is the total ionic compound.
Ca2+ + SO2 --> CaSO4 ?
Except for |dw:1406600706900:dw| perfect!
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