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Chemistry 17 Online
OpenStudy (anonymous):

Why is it better to write a net ionic equation for this reaction (justify): Ca(OH)2(aq) + Na2SO4 --> ?

OpenStudy (anonymous):

@JoannaBlackwelder

OpenStudy (joannablackwelder):

That depends on what you are writing the reaction for. Is there any more context to this problem?

OpenStudy (anonymous):

"conditions around a hydrothermal vents deep in the ocean floor can enable chemical reactions that produce solid materials. A student models one of these reactions by combining aqueous Ca(OH)2 and Na2SO4, and observes the formation of a solid in a liquid. Justify the choice of a net ionic equation for describing this reaction and write the balanced net ionic equation."

OpenStudy (anonymous):

@JoannaBlackwelder

OpenStudy (joannablackwelder):

A reaction of aqueous solutions to produce a solid and a liquid sounds like a precipitation reaction to me.

OpenStudy (joannablackwelder):

The net ionic reaction shows how the precipitate is formed and everything else just stays as ions in solution.

OpenStudy (joannablackwelder):

Net reactions are always useful for precipitation reactions. Make sense?

OpenStudy (anonymous):

yeah... how do I make a net ionic equation for this? @JoannaBlackwelder

OpenStudy (joannablackwelder):

First, do double replacement.

OpenStudy (joannablackwelder):

Then check your products to determine which one is the precipitate and which one stays in solution using a solubility table.

OpenStudy (anonymous):

Ca(OH)2(aq) + Na2SO4 --> CaSO4 + 2NaOH

OpenStudy (joannablackwelder):

Yup

OpenStudy (anonymous):

the precipitate is CaSO4

OpenStudy (joannablackwelder):

Good. :)

OpenStudy (anonymous):

what now?

OpenStudy (joannablackwelder):

Now we need to write the reactants and products as they would be in solution, as ions (for everything except the precipitate).

OpenStudy (joannablackwelder):

So, Ca(OH)2 would be Ca2+ + 2OH-, for example.

OpenStudy (anonymous):

huh?

OpenStudy (joannablackwelder):

Ca(OH)2 written as ions is \[Ca ^{2+}+2OH ^{-}\]

OpenStudy (joannablackwelder):

This is how the compound exists in solution (aqueous)

OpenStudy (anonymous):

oh ok yeah

OpenStudy (joannablackwelder):

Can you write out the other aqueous compounds as ions?

OpenStudy (anonymous):

Na2SO4 --> Na1+ + 4SO 2NaOH --> 2Na+ + 2OH- ?

OpenStudy (joannablackwelder):

NaOH looks good! :)

OpenStudy (joannablackwelder):

Look at Na2SO4 again.

OpenStudy (anonymous):

hmmm... not really sure how to do this

OpenStudy (joannablackwelder):

\[Na _{2}SO _{4}\rightarrow2Na ^{+}+SO _{4}^{2-}\]

OpenStudy (joannablackwelder):

Make sense?

OpenStudy (anonymous):

why is na only + and so is 2-?

OpenStudy (joannablackwelder):

Na has 1 valence electron, and it loses that electron to make an ion, making it +1

OpenStudy (anonymous):

oh ok

OpenStudy (joannablackwelder):

SO4 is a polyatomic ion that has a charge of 2-

OpenStudy (anonymous):

got it got it

OpenStudy (joannablackwelder):

:)

OpenStudy (joannablackwelder):

So, can you write the whole reaction with the aqueous compounds as ions?

OpenStudy (anonymous):

Ca(OH)2(aq) + Na2SO4 --> 2Na+ + SO2− + 2Na+ + 2OH-

OpenStudy (joannablackwelder):

\[Ca ^{2+}+2OH ^{-}+2Na ^{+}+SO _{4}^{2-}rightarrowCaSO _{4}+ 2Na ^{+}+2OH ^{-}\]

OpenStudy (joannablackwelder):

Make sense?

OpenStudy (anonymous):

OHHHHHHH that makes a lot more sense

OpenStudy (joannablackwelder):

:)

OpenStudy (joannablackwelder):

Now cancel out anything that is on both sides.

OpenStudy (anonymous):

is that my net ionic equation though?

OpenStudy (joannablackwelder):

No, that is the total ionic compound.

OpenStudy (anonymous):

Ca2+ + SO2 --> CaSO4 ?

OpenStudy (joannablackwelder):

Except for |dw:1406600706900:dw| perfect!

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