A rectangle has an area of x^2-y^2 square units. What is the width of the rectangle

Question

solomonzelman · Answer

Well, they are probably looking for  something like    $\normalsize\color{blue}{   x^2-y^2=(x+y)~~(x-y)   }$
                                                                                         $\normalsize\color{blue}{   ↓    }$               $\normalsize\color{blue}{   ↓    }$            $\normalsize\color{blue}{   ↓    }$
                                                                                    $\normalsize\color{blue}{ \rm {Area}=~~~~Width~\times ~Length   }$

solomonzelman · Answer

See ?

anonymous · Answer

Oh, so can the width be either x-y, or x+y?

solomonzelman · Answer

yes, it doesn't matter which one is width and which one is length.

anonymous · Answer

Thanks soooo much!

solomonzelman · Answer

Anytime...

anonymous · Answer

Can I ask you another question please

solomonzelman · Answer

Yes sure.

anonymous · Answer

If a rectangle has an area of x^2-2x square units. The lenght would be either x or x-2, right?

solomonzelman · Answer

`x²-2x`  =  ` x`    ×      `(x+2)`
   ↓            ↓                 ↓
`AREA`   =  `Length`  ×  `Width`

solomonzelman · Answer

Like this.

solomonzelman · Answer

(For next question, please make a new post)

anonymous · Answer

Thank you. Does it matter which one is the lenght and which one is the widh?

anonymous · Answer

Ok

solomonzelman · Answer

No, it doesn't matter which one is height and which one is length:)