Question

How many milliliters of a 0.100 M NaOH solution are required to neutralize 25.0 milliliters of 0.150 M HCl?
Answer

25.0 ml

37.5 ml

125 ml

167 ml

Answer 1

@Abhisar @aaronq

Answer 2

@ganeshie8

Answer 3

This one I have no idea...what equation would I even use?

Answer 4

Ok first see the equation

Answer 5

\(\sf \large NaOH + HCl-->NaCl+H_2O\)

Answer 6

ok...

Answer 7

No of moles in 25.0 milliliters of 0.150 M HCl = (25*0.150)/1000= ?

Answer 8

Now same amount of NaOH will be required to neutralize it since the ratio of NaOH and HCl is 1:1 in the reactant side.

Answer 9

.025?
wait...still working, ok

Answer 10

wait...actually...is it 37.5?

Answer 11

(I'm no chem wiz obviously lol)

Answer 12

\(\color{blue}{\text{Originally Posted by}}\) @HourglassMage
wait...actually...is it 37.5? \(\huge\checkmark\)
\(\color{blue}{\text{End of Quote}}\)

Answer 13

Woooooowwwwww I've been quoted!!
Lmao, thnx for all your help. I have one more question if you're up for it.

Answer 14

Go ahead !

Answer 15

Which atoms have undergone oxidation and reduction.

2HNO3 + S -> 2NO + H2SO4

Answer 16

Do you know how to calculate oxidation number ?

Answer 17

no, but I don't want to do extra work really cause I really have to use the loo

Answer 18

O_o

Answer 19

what? I drank a lot of coffee, alright....and this is the last question on the exam

Answer 20

Well it is against the code of conduct to use this website for purposes like cheating !

Answer 21

If a mod sees this, he will certainly suspend you !

Answer 22

huh? No, I meant extra work, not work beyond what I have to do to find which one oxidizes and which one reduces..unless finding the oxidation and reduction numbers is necessary, which based on your response, I guess it is...*sigh*

Answer 23

You will have to find oxidation states in order to know which one is oxidised and which one is reduced.

Answer 24

ah well
how do I find those?

Answer 25

http://www.chemguide.co.uk/inorganic/redox/oxidnstates.html

Answer 26

Here you can learn...however i will tell u the oxidation states for this question.

Answer 27

\(\color{blue}{\text{Originally Posted by}}\) @HourglassMage
Which atoms have undergone oxidation and reduction.

2HNO3 + S -> 2NO + H2SO4
\(\color{blue}{\text{End of Quote}}\)

Is there any option ?

Answer 28

In HNO3
H=+1
N=+5
O=-2

Answer 29

S=0

Answer 30

NO
N=+2
o=-2

Answer 31

H2SO4
H=+1
S=+6
O=-2

Answer 32

The one whose oxidation state increases is oxidised and the one whose decreases is reduced.

Answer 33

For S it was 0 before and now it is +6. So it is oxidised.

Answer 34

Which one is reduced ?