Find the first six terms of the sequence.

a1 = -4, an = an-1 + 7

Question

Find the first six terms of the sequence.

a1 = -4, an = an-1 + 7

solomonzelman · Answer

$\large\color{blue}{  a_1=-4   }$  saying that the 1st term is `-4`.

$\large\color{blue}{  a_n=a_{n-1}+7   }$,  this means that the difference is equal to `7`.

hang254 · Answer

ok, so would i add 7 after -4 and so on?

solomonzelman · Answer

$\large\color{blue}{  a_n=a_1 + d(n-1)   }$,   and in your case,    $\large\color{blue}{  a_5=a_1 + d(5-1)   }$ since looking for the fifth term.

Plug in the `a1` and the difference that you know., and you get

$\large\color{blue}{  a_5=-4 + 7(5-1)   }$

solomonzelman · Answer

So,   $\large\color{black}{  a_5=??? ~~~~~~~\rm{(you~~~tell~~~me)}   }$

hang254 · Answer

12

solomonzelman · Answer

$\large\color{blue}{  a_5=-4 + 7(5-1)   }$

$\large\color{blue}{  a_5=-4 + 7(4)   }$

$\large\color{blue}{  a_5=-4 +28 }$

$\large\color{blue}{  a_5=?  }$   (not 12)

hang254 · Answer

omg i forgot to do PEMDAS, lol sorry

24

hang254 · Answer

that makes more sense now

hang254 · Answer

so it would be:
-4, 3, 10, 17, 24, 31
for the first 6 terms