Question

Find the first six terms of the sequence.

a1 = -4, an = an-1 + 7

Answer 1

\(\large\color{blue}{ a_1=-4 }\) saying that the 1st term is `-4`.

\(\large\color{blue}{ a_n=a_{n-1}+7 }\), this means that the difference is equal to `7`.

Answer 2

ok, so would i add 7 after -4 and so on?

Answer 3

\(\large\color{blue}{ a_n=a_1 + d(n-1) }\), and in your case, \(\large\color{blue}{ a_5=a_1 + d(5-1) }\) since looking for the fifth term.

Plug in the `a1` and the difference that you know., and you get

\(\large\color{blue}{ a_5=-4 + 7(5-1) }\)

Answer 4

So, \(\large\color{black}{ a_5=??? ~~~~~~~\rm{(you~~~tell~~~me)} }\)

Answer 5

12

Answer 6

\(\large\color{blue}{ a_5=-4 + 7(5-1) }\)

\(\large\color{blue}{ a_5=-4 + 7(4) }\)

\(\large\color{blue}{ a_5=-4 +28 }\)

\(\large\color{blue}{ a_5=? }\) (not 12)

Answer 7

omg i forgot to do PEMDAS, lol sorry

24

Answer 8

that makes more sense now

Answer 9

so it would be:
-4, 3, 10, 17, 24, 31
for the first 6 terms