Need help solving please, The measure of angle A to the nearest tenth of a degree is:

https://banff.owschools.com/media/g_geo_2013/5/69_355.gif

I do not really understand the sine thing, so far i just have sin= 1/3 ? i dont know how to solve... thanks

If anyone could explain in a simple way how to use sine i would greatly appreciate it, I over think when it comes to math :/

Question

Need help solving please, The measure of angle A to the nearest tenth of a degree is:

https://banff.owschools.com/media/g_geo_2013/5/69_355.gif

I do not really understand the sine thing, so far i just have sin= 1/3 ? i dont know how to solve... thanks

If anyone could explain in a simple way how to use sine i would greatly appreciate it, I over think when it comes to math :/

phi · Answer

anonymous · Answer

|dw:1406733678124:dw|
we should find AB.
$$9+x^2=81$$$$x^2=73$$$$x=\sqrt{73}=8.544$$
now you can find sin A with using AB AND AC.

anonymous · Answer

Thank you, Would you happen to know how to use sine on a ti-84 ?

anonymous · Answer

$$A=\sin ^{-1}\left(\frac{3}{6}\right)=\frac{\pi }{6}=30 {}^{\circ} $$