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cot(x)sec^4(x)=cot(x)+2tan(x)+tan^x please do this step by step so i can get a good grasp on what is happening
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USE: sec^2(x) = 1+tan^2(x)
how did you get that.
Well, sec^2(x) = 1+ tan^2(x) is an identity
like sin^2(x) + cos^2(x)=1
from the defination of trigonometric ratios, we have |dw:1406809830085:dw|
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now, sec^2(x) = h^2/b^2 = (p^2 + b^2)/b^2 = p^2/b^2 +1 = tan^2(x) + 1
i just need to prove the identity
Now, you need to use sec^2(x) = 1 + tan^2(x) to Prove cot(x)sec^4(x)=cot(x)+2tan(x)+tan^3(x)
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