How much heat is necessary to melt 56.72 grams of substance Y from solid phase at 15 degrees Celsius to liquid at the same temperature?

Melting point of substance Y = 15 degrees Celsius; ∆Hvaporization = 2.83 J/mol; ∆Hfusion = 5.51 J/mol; MWsubstance y = 14.77 g/mol.

A. 21.2 J
B. 3.13 x 102 J
C. 10.9 J
D. 161 J

Question

How much heat is necessary to melt 56.72 grams of substance Y from solid phase at 15 degrees Celsius to liquid at the same temperature?

Melting point of substance Y = 15 degrees Celsius; ∆Hvaporization = 2.83 J/mol; ∆Hfusion = 5.51 J/mol; MWsubstance y = 14.77 g/mol.

A. 21.2 J
B. 3.13 x 102 J
C. 10.9 J
D. 161 J

aravindg · Answer

Essentially this involves conversion of state.
Heat required=mL 

Where m is mass of substance and L is latent heat required.

aravindg · Answer

Note that direct plugging in of values won't work since L is given in J/mol and mass is in  grams. Convert to appropriate units so that the mass cancels out and we get Joules on right side.

anonymous · Answer

So how do you do that @AravindG?