Question

http://prntscr.com/48f9kx

Answer 1

so, you cant have 0 in the denominator because you cant divide by 0. would any of the answers cause the bottom to be 0?

Answer 2

your profile says that you are offline :P

Answer 3

i dunno sometimes this place doesnt like that I use Linux shells to open the webpage

Answer 4

Linux shells?

Answer 5

Um, linux is an operating system, like Microsoft Windows or Mac OS... but different.

Answer 6

@dannyrod2000 Did you get the answer? :)

Answer 7

oh ok

Answer 8

would it be C?

Answer 9

no.. think about this:
\[7(x+6)\]
what causes that to be 0? and is that an answer?

Answer 10

No.

Find out where the function will be undefined.

If f(x) is a function. It is always undefined if it takes this form: \(\frac{0}{0}\)
When does the function you are given take that form? :)

Answer 11

D?

Answer 12

ok now i am guessing lol

Answer 13

Don't guess. It never helps!

\[\frac{(x-2)(x+6)}{7(x+6)} = \frac{(x-2)}{7}\]
\[\frac{(x-2) \cancel{(x+6)}}{7 \cancel{(x+6)}} = \frac{(x-2)}{7}\]
\[\frac{(x-2)}{7} = \frac{(x-2)}{7}\]

This implies that, for all real number x, the function will equal \(\frac{(x-2)}{7}\)

Can this be done?
What's your answer?

Answer 14

i am a little confused.

Answer 15

I think it would be easier for you think about what I said, what value for x would cause this to equal 0?
\[7(x+6)\]

Answer 16

B?

Answer 17

Why B?

Can you answer?

Answer 18

Why not A?

Answer 19

-6 and 6 is 0

Answer 20

Yes, and? Why are excluding it though?

Answer 21

Because, when x = -6.

\[\frac{(x-2)(x+6)}{7(x+6)}\] becomes
\[\frac{(x-2)(0)}{7(0)}\]

And as i said before, \[\frac{0}{0}\] is in an indeterminate form. That is the reason why x can be all real numbers but not -6 here!

Getting this?

Answer 22

thanks for the help! @agreene @AkashdeepDeb