Question

I need help on questions 8,9 and 10!!
http://static.k12.com/eli/bb/1211/5_68981/1_124249_20_69001/fd27e95748792f7c2f1d1f347a2cd56e6750b95d/media/7c533c33854b5d80d74ef525470a41d5dc1f7aba/AAHS_M5S5L8_1_teacher_graded_assignment_PROJECTGUIDE.pdf

Answer 1

@dg2

Answer 2

post first question

Answer 3

for there to be 2 solutions the discriminant must be more than 0

Answer 4

for ther to be 1 solution, the discriminant must equal zero
for there to be no solutions, the discriminant must be less than zero
lol just had a quadratics test today

Answer 5

okay one sec

Answer 6

Think of another quadratic equation that has two (2) real number solutions. Write the
equation in ax^2+ bx+ c =0 form. Then find the value of the discriminant to support your
answer.

Answer 7

ok so the discriminat must be more than 0

Answer 8

Follow the directions for each problem to write a quadratic equation that has the given number of
solutions. Be sure to show all the work leading to your answer.
those are the directions

Answer 9

For example
\[x^2 +3x+3=0\]
therefore the discriminant of the equation =\[b^2 - 4ac\]
=\[3^2 - 4\times1\times2\]
=1
Because the discriminant (1) is more than zero, therefore there are two solutions

Answer 10

oh okay i kinda get it

Answer 11

#9?

Answer 12

When Discriminant = 0, it has 2 real and equal solutions
When Discriminant > 0, it has 2 real solutions
When Discriminant < 0, it has 0 real solutions

Answer 13

thanks for the tip:)