What is the equation of the line that contains the point (–5, –1) and has a slope of 4? Write in slope-intercept form. Im sorry I really don't understand slope intercept
The easiest way is to write it in point slope form first. To do this follow the form y-k = s(x-h) where k is your y coordinate point, and h is your x coordinate point and s is your slope. If we do this with your equation, what would we get?
well the slope is 4 and -5,-1 are the coordinates all we do is plug them in right?
Correct!
I get it now! I didn't realize that's all you had to do is plug it in to the formula thanks guys:)
That isn't all. That puts it in point-slope form.
You want slope-intercept form, which is one extra step.
Anytime.
theres an extra step?
Let's use an example, say my slope is 2, and I get a point of (1, 3). Point slope would be y-3 = 2(x-1) Slope intercept is the form y = mx + b If I make it easier to follow that form, y = 2(x-1) + 3 *Hint* What if we distribute the 2 ;)
it would simplify the problem right?
y = 2x - 2 + 3 which equals y = 2x + 1 Which form does y = 2x + 1 follow? Point slope, or your slope intercept?
slope intercept because y=mx+b correct?
Yes ma'am. :) Now just do the same with your problem. Put it into point slope form. And then get y on the left, and everything else on the right. And then distribute your slope and simplify. Problem = solved.
thankyou:) no one has ever shown me that extra step!
You are very welcome. Thank for your dedication to learning!
well thankyou for making me understand as well as taking the time to explain it!
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